Subspace vs Subset: Inheritance of Topology

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When Y is a subspace of X and A is a subset of Y, the topology A inherits from Y is equivalent to the topology it inherits from X. The open sets in the topology of A from Y, denoted T_Y, consist of intersections of open sets in Y with A. To demonstrate that T_Y is a subset of T_X, one must show that any open set U in T_Y can be expressed as an intersection with an open set U'' in X. This involves identifying an open set U' in Y that leads to the conclusion that U is also in T_X. The discussion emphasizes the relationship between subspaces and subsets in topology.
tomboi03
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Hey guys...

I'm not sure how I'm suppose to show that if Y is a subspace of X, and A is a subset of Y, then the topology A inherits as a subspace of Y is the same as the topology it inherits as a subspace of X.

I know that a subspace is... Ty = {Y\capU| U \inT}
meaning that its open sets consist of all intersections of open sets of X with Y.
and that a subset is every element of A is also an element of B.

pretty much right? so how do i express this in terms of subset and subspace?
 
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Let TY denote the topology inherited from Y, and TX the topology inherited from X, i.e.
T_Y = \{ U \cap A | U \text{ is open in } Y \}
and
T_X = \{ V \cap A | V \text{ is open in } X \}

First let's show that T_Y \subseteq T_X. Let U \in T_Y be an open set in the Y-induced topology on A. That means there is some open set U' in Y, such that U = A \cap U'. Can you find a set U'' which is open in X, such that U = A \cap U''? Because that would show that
U \in T_Y \implies U \in T_X
and therefore
T_Y \subseteq T_X.
 

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