- #1

Yazan975

- 30

- 0

View attachment 8419

What I have done:

I changed all fractions to common denom and that gave me

5y-5x=1 (1) *I numbered the fractions

5y+2x=5 (2)

Then: 5y=5-2x

Substitute into equation 1

(5-2x)-5x=1

5-7x=1

x=4/7

Thing is my answer says I should be getting x=0

Any hints?

What I have done:

I changed all fractions to common denom and that gave me

5y-5x=1 (1) *I numbered the fractions

5y+2x=5 (2)

Then: 5y=5-2x

Substitute into equation 1

(5-2x)-5x=1

5-7x=1

x=4/7

Thing is my answer says I should be getting x=0

Any hints?