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Suicide substrate and kinetics

  1. May 12, 2010 #1
    Suicide substrate. An Enzyme, E reacts with a substrate S to form an enzyme substrate-complex, ES is usual for Michaelis-Menten kinetics. However, the substrate in the enzyme-substrate complex chemically reacts with the enzyme to form a permanent covalent complex at the enzyme active site. The enzyme then becomes ED (dead enzyme). ED is no longer active and it does not turn over.

    The reaction shceme is

    E+S--> (k1) and <--- (k-1) ES---> (k2) ED

    In this case [ET] -[ED]=[E] +[ES], where [ET] is the initial starting concentration of enzyme, [ED] is the concentration of dead enzyme,and [E] and [ES] are the concentration of viable enzyme that are respectively free and substrate bound.

    Using the steady state approximation for [ES], as you would in the usual Michaelis-Menten scheme, derive an expression for the rate of creation of [ED]. That is, find d[ED]/dt. (Hint, your expression will contain the term {[ET]-[ED]} instead of the usual [ET]. Your expression also contains k1, k-1, k2)

    I doubt I'm right on this...

    d[ES]/dt = k1[E] - [ES](k-1 + k2)

    d[ED]/dt = k2 [ES]

    = k1([ET]-[ES]) - [ES](k-1 + k2)

    Am I at least on the right track? If not I have a couple ideas to alternative solutions.
     
  2. jcsd
  3. May 12, 2010 #2

    Ygggdrasil

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    These two expressions are correct and a good starting point.



    I'm not sure what you did to get here.

    Anyway, the problem tells you to use the steady state approximation. What is the steady state approximation and what does it tell you about one of your equations?

    Also, you want to write an expression for d[ED]/dt in terms of [ET], [ED], k1, k-1, k2, and . This means you need to find some way of expressing [ES] and [E] in these terms.
     
  4. May 12, 2010 #3
    site screwed up my last post...

    ok, so with steady state i can assume negligible change in ES

    with ET-ED being the total enzyme I got:

    ([ET]-[ED]) = [ES] + [ES] ((k-1 + k2)/k1)

    i hope this is a little closer than the last one.
     
    Last edited: May 12, 2010
  5. May 12, 2010 #4

    Ygggdrasil

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    That looks correct. Now, you just have to combine this information with your equation for d[ED]/dt.
     
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