Sum of Forces in X and Y Directions - axis set up normally

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Homework Help Overview

The discussion revolves around calculating the sum of forces in the X and Y directions, with a focus on vector components and their respective signs based on a standard Cartesian coordinate system setup. The original poster expresses uncertainty regarding their calculations and the interpretation of angles related to force vectors.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the application of trigonometric equations to find the components of a force vector, questioning how to correctly interpret the angles and signs of these components. There is a focus on the relationship between the angle of the force and its position relative to the axes.

Discussion Status

Some participants have provided guidance on visualizing the vector components and their signs, suggesting that redrawing the vector may clarify the situation. There is ongoing exploration of the implications of the angles and the correct application of the equations.

Contextual Notes

Participants note the importance of including diagrams for clarity and emphasize the need for detailed work to facilitate better assistance. There is mention of specific angles and their relation to the coordinate axes, which may influence the calculations.

cdornz
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Being asked for the sum of forces in the X and Y directions and the axis are set up 'normally' so like a plus sign ( + ).

I attempted the first one and I think I did it correctly, but I'm not so sure about the second one.
 

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The first one is fine. Where's your work on the second one?

Note: While a diagram is useful for reference, please type up your work right here in the thread. That helps people give you better help.

Please see: How to Ask for Help
 
So I was looking through my notes, and I saw the equation Vx = Vcosθ and Vy = Vsinθ.

I'm not sure though that this is where i can put these equations to use, since i don't know the value of V. In looking at the angles, F1 is 60° from the x-axis going counterclockwise. I'm lost in more of how to put the information I do know together.
 
cdornz said:
So I was looking through my notes, and I saw the equation Vx = Vcosθ and Vy = Vsinθ.
That's how you'd find the x and y components of some vector V, where θ is the angle made with the +x axis.

I'm not sure though that this is where i can put these equations to use, since i don't know the value of V.
According to the diagram, it would be F1.

In looking at the angles, F1 is 60° from the x-axis going counterclockwise.
F1 is 60° below the negative x axis. So will the x-component of F1 be negative or positive?
 
If the x-component is below the negative x-axis i would think that that component would be negative. But using those equations I think I've determined the answer.

F1x=F1cos60°
F1y=F1sin30°

I broke this down by drawing out the picture of the triangle somewhat given and by finding the f1x and f1y components and plugging those into the equations I had.
 
cdornz said:
If the x-component is below the negative x-axis i would think that that component would be negative. But using those equations I think I've determined the answer.

F1x=F1cos60°
F1y=F1sin30°

I broke this down by drawing out the picture of the triangle somewhat given and by finding the f1x and f1y components and plugging those into the equations I had.
Looks OK except for the signs.
 
In question with the signs, would the x-component be negative because it is technically below the F1 and the y-component positive because it is technically above the F1?
 
cdornz said:
In question with the signs, would the x-component be negative because it is technically below the F1 and the y-component positive because it is technically above the F1?
Hint: Redraw the vector F1 so its tail is at the point of application. Or at least imagine a set of axes with the origin at the tail of F1. That will make it easier to see the signs of the components.

The x-component of F1 is negative since F1 points to the left of the vertical axis.

The y-component of F1 is negative since F1 points below the horizontal axis.
 

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