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1+2+3+...=[itex]\frac{n(n+1)}{2}[/itex]

1^{2}+2^{2}+3^{2}=[itex]\frac{n(n+1)(2n+1)}{6}[/itex]

I want to know what the general formula of Ʃn^{a}, in which n and a are natural numbers, respect to n and a.

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# Sum of the powers of natural numbers

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