MHB Summation and product notation rules

Click For Summary
The discussion focuses on the validity of statements regarding summation and product notation rules. The user initially believes that only two statements are correct and identifies the third statement as incorrect, specifically regarding the distribution of a constant across a product. The conclusion confirms that the user's assessment is accurate, affirming that the third statement does not hold true. The conversation emphasizes the importance of understanding the properties of summation and product notation in mathematical expressions. Overall, the user successfully clarifies their understanding of the rules.
lemonthree
Messages
47
Reaction score
0
As per the image, I am supposed to select all the valid statements. Apparently I'm only partially correct, and so I took another look at the statements.

I believe the third statement is wrong, since $$c * (a_m*a_{m+1}*a_{m+2}*...*a_n)$$ =/= $$ (c*a_m)(c*a_{m+1})(c*a_{m+2})*...*(c*a_n)$$

Thus there should only be two answers. Am I correct on this?
 

Attachments

  • Capture.JPG
    Capture.JPG
    23.1 KB · Views: 134
Physics news on Phys.org
You are correct.

-Dan
 
The standard _A " operator" maps a Null Hypothesis Ho into a decision set { Do not reject:=1 and reject :=0}. In this sense ( HA)_A , makes no sense. Since H0, HA aren't exhaustive, can we find an alternative operator, _A' , so that ( H_A)_A' makes sense? Isn't Pearson Neyman related to this? Hope I'm making sense. Edit: I was motivated by a superficial similarity of the idea with double transposition of matrices M, with ## (M^{T})^{T}=M##, and just wanted to see if it made sense to talk...

Similar threads

  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
5K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 9 ·
Replies
9
Views
1K
  • · Replies 31 ·
2
Replies
31
Views
2K
Replies
10
Views
2K
  • · Replies 1 ·
Replies
1
Views
796
  • · Replies 1 ·
Replies
1
Views
2K