Supernova Explosion: 720 Light-Years Away from Earth

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SUMMARY

The discussion focuses on calculating the time elapsed since a supernova explosion as observed from a spacecraft traveling at 0.77c, which is 720 light-years away from Earth. The observer on Earth notes that the light from the supernova reaches the spacecraft after 720 years. The correct approach involves using the Lorentz transformation for time dilation, specifically the equation Δt' = Δt / √(1 - v²/c²). The user initially misapplies the formula but is guided to correctly transform the spacetime coordinates between the Earth and the spaceship frames.

PREREQUISITES
  • Understanding of special relativity concepts, particularly time dilation
  • Familiarity with Lorentz transformations
  • Basic knowledge of light-year as a unit of distance
  • Ability to manipulate algebraic equations involving velocity and the speed of light
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  • Study the Lorentz transformation equations in detail
  • Practice problems involving time dilation and length contraction
  • Explore the implications of traveling at relativistic speeds on time perception
  • Learn about spacetime diagrams and their applications in special relativity
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Students of physics, particularly those studying special relativity, educators teaching advanced physics concepts, and anyone interested in the implications of relativistic travel on time and space.

kvan
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Homework Statement



A space craft, traveling at 0.77c, is just passing the Earth when the light from a Supernova which is traveling in exactly the opposite direction to the ship, reaches it. According to an observer on the Earth the star which caused the explosion was 720 light years away (1 light year = distance traveled by light in one year). According to an observer on the spaceship how long ago did the star explode?

Homework Equations



I tried using:

[tex] \Delta tsingle-quote=\frac{\Delta t}{\sqrt{1-\frac{v^2}{c^2}}} [/tex]

The Attempt at a Solution



As there is a distance of 720 light years between the supernova and the Earth, it takes light 720 years for light to reach Earth, so I used that value for t. I then used the value of 0.77c for velocity and left c as is. With these numbers I get the equation

[tex]\Delta tsingle-quote=\frac{720 years}{\sqrt{1-\frac{0.77c^2}{c^2}}}[/tex]

I tried putting in the Latex equation for it but still not really that great at it sorry. But I'm trying to use the lorentz transformation for time dilation of

Delta t' = delta t/ sqrt(1 - v^2/c^2)
But the answer is incorrect, any hints or ideas?
 
Last edited:
Physics news on Phys.org
Fixed your LaTeX.
kvan said:

Homework Statement



A space craft, traveling at 0.77c, is just passing the Earth when the light from a Supernova which is traveling in exactly the opposite direction to the ship, reaches it. According to an observer on the Earth the star which caused the explosion was 720 light years away (1 light year = distance traveled by light in one year). According to an observer on the spaceship how long ago did the star explode?

Homework Equations



I tried using:

[tex]\Delta t'=\frac{\Delta t}{\sqrt{1-\frac{v^2}{c^2}}}[/tex]

The Attempt at a Solution



As there is a distance of 720 light years between the supernova and the Earth, it takes light 720 years for light to reach Earth, so I used that value for t. I then used the value of 0.77c for velocity and left c as is. With these numbers I get the equation

[tex]\Delta t'=\frac{720 years}{\sqrt{1-\frac{0.77c^2}{c^2}}}[/tex]

I tried putting in the Latex equation for it but still not really that great at it sorry. But I'm trying to use the lorentz transformation for time dilation of

Delta t' = delta t/ sqrt(1 - v^2/c^2)
But the answer is incorrect, any hints or ideas?
 
You need to use the Lorentz transformations because the events are separated by both time and space in both frames.

Find the spacetime coordinates of the explosion in the Earth's frame, and then transform them to coordinates in the spaceship's frame.
 

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