- #1
Karolus
- 92
- 8
What is the "superposition principle"?
I have a confusion about one of the fundamental concepts of quantum mechanics, the principle of superposition
This sounds, more or less: a linear combination with arbitrary coefficients of different quantum states is a new quantum state
If I have (for maximum simplicity) two quantum states ##|a_1\rangle## and ##|a_2\rangle##, I can "build" a new state
## |a_3\rangle = c_1|a_1\rangle + c_2|a_2\rangle ##
Where ##c_1## and ##c_2## are arbitrary coefficients
But what does ##|a_3\rangle## represents?
Things become embarrassed if we think in terms of eigenvectors.
Let's recap the problem in these terms:
Let A be a observable generic (hermitian matrix) and ##|a_k\rangle## the set of eigenvectors and eigenvalues ##\lambda_k##.
Let's exclude cases of "degenerate" for simplicity.
We know that ##\{|a_k\rangle\}## is a complete set in Hilbert's space.
What does it mean?.
It means that ##\{|a_k\rangle\}##is an orthonormal base of Hilbert space, so any "vector" of Hilbert space
Is represented by a suitable linear combination of ##|a_k\rangle##.
Now, it's not true at all that a linear combination of ##|a_k\rangle## is still an eigenvector of A
On the other hand, we think of the hydrogen atom.
The eigenfunctions of the hydrogen atom ##|\psi_i\rangle## (suppose in its simplest form) with eigenvalues ##E_i##
Let's suppose they answer the equation ##H|\psi_i\rangle = E_i|\psi_i\rangle##
In what way a linear combination of hydrogen eigenstates is a quantum state?
It is usually represented as a generic quantum state of the hydrogen atom as a combination
Linear of all its eigenstates like ##|\psi\rangle = \sum_{i}c_i|\psi_i\rangle##. A possible measure will collapse the generic ##|\psi\rangle##
in one of the ##|\psi_i\rangle## with probabilty ##|c_i|^2##
How does this result prove?
I have a confusion about one of the fundamental concepts of quantum mechanics, the principle of superposition
This sounds, more or less: a linear combination with arbitrary coefficients of different quantum states is a new quantum state
If I have (for maximum simplicity) two quantum states ##|a_1\rangle## and ##|a_2\rangle##, I can "build" a new state
## |a_3\rangle = c_1|a_1\rangle + c_2|a_2\rangle ##
Where ##c_1## and ##c_2## are arbitrary coefficients
But what does ##|a_3\rangle## represents?
Things become embarrassed if we think in terms of eigenvectors.
Let's recap the problem in these terms:
Let A be a observable generic (hermitian matrix) and ##|a_k\rangle## the set of eigenvectors and eigenvalues ##\lambda_k##.
Let's exclude cases of "degenerate" for simplicity.
We know that ##\{|a_k\rangle\}## is a complete set in Hilbert's space.
What does it mean?.
It means that ##\{|a_k\rangle\}##is an orthonormal base of Hilbert space, so any "vector" of Hilbert space
Is represented by a suitable linear combination of ##|a_k\rangle##.
Now, it's not true at all that a linear combination of ##|a_k\rangle## is still an eigenvector of A
On the other hand, we think of the hydrogen atom.
The eigenfunctions of the hydrogen atom ##|\psi_i\rangle## (suppose in its simplest form) with eigenvalues ##E_i##
Let's suppose they answer the equation ##H|\psi_i\rangle = E_i|\psi_i\rangle##
In what way a linear combination of hydrogen eigenstates is a quantum state?
It is usually represented as a generic quantum state of the hydrogen atom as a combination
Linear of all its eigenstates like ##|\psi\rangle = \sum_{i}c_i|\psi_i\rangle##. A possible measure will collapse the generic ##|\psi\rangle##
in one of the ##|\psi_i\rangle## with probabilty ##|c_i|^2##
How does this result prove?