Supposedly easy arcsine problem

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SUMMARY

The discussion centers around solving the equation sin(x) = 1/5, specifically finding x in closed form using the arcsine function. The conclusion reached is that arcsin(1/5) does not yield a simpler closed form expression, confirming that it is indeed a valid calculus problem. The tutor expresses skepticism about the problem's fairness for a Calculus 1 course, suggesting that the solution involves complex numbers or series for further exploration.

PREREQUISITES
  • Understanding of trigonometric functions and their inverses, specifically arcsin.
  • Familiarity with differential calculus concepts.
  • Basic knowledge of complex numbers and series expansions.
  • Ability to manipulate and solve equations involving trigonometric identities.
NEXT STEPS
  • Research the properties and applications of the arcsine function in trigonometry.
  • Learn about series expansions for trigonometric functions, particularly Taylor series.
  • Explore the use of complex numbers in solving trigonometric equations.
  • Investigate the implications of inverse trigonometric functions in calculus problems.
USEFUL FOR

Students and tutors in calculus, particularly those dealing with trigonometric equations and inverse functions, as well as educators looking to clarify the complexity of such problems in a Calculus 1 context.

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Homework Statement



find x if sin(x)=1/5

Homework Equations



x=arcsin(1/5)= ??something in closed form maybe??

The Attempt at a Solution



This actually isn't my homework. A student I am tutoring in differential calculus came to me with this problem and I am convinced it is a typo. Just for certainty, is there a closed form for this? I started messing around with complex numbers and series... so i thought it might be time to ask here.
Thanks!
 
Last edited:
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so i just want to confirm that it is not really a fair and square Cal 1 problem...
 
I doubt you are going to find a neater form for that. It's arcsin(1/5).
 

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