Surjection Between Mapping Class Grp. and Symplectic Matrices

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SUMMARY

The discussion centers on the natural surjection between the mapping class group Mg and the group of symplectic 2g x 2g matrices. This surjection is linked to the action of Mg on the first homology group H1(Sg, Z), induced by Dehn twists. The kernel of this action is identified as the Torelli group, which consists of automorphisms that induce the identity map in homology. The conversation highlights the relationship between the mapping class group and symplectic geometry, emphasizing the preservation of the cup product and the antisymmetry of the bilinear form in this context.

PREREQUISITES
  • Understanding of mapping class groups, specifically Mg
  • Familiarity with symplectic matrices and their properties
  • Knowledge of homology theory, particularly H1(Sg, Z)
  • Concept of the Torelli group and its significance in algebraic topology
NEXT STEPS
  • Research the properties of Dehn twists and their role in the mapping class group
  • Study the relationship between homology and symplectic geometry
  • Explore the structure and applications of the Torelli group in algebraic topology
  • Investigate level-2 prime congruence subgroups of Sp(2g, Z)
USEFUL FOR

Mathematicians, particularly those specializing in algebraic topology, symplectic geometry, and the study of mapping class groups. This discussion is beneficial for anyone looking to deepen their understanding of the connections between these areas.

Bacle
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Hi, Everyone:

I am reading a paper that refers to a "natural surjection" between M<sub>g</sub>

and the group of symplectic 2gx2g-matrices. All I know is this map is related to some

action of M<sub>g</sub> on H<sub>1</sub>(S<sub>g</sub>,Z). I think this

action is define by/as the induced maps on homology by the D<sub>i</sub> , i.e.,

the Dehn twists that generate S<sub>g</sub>. I think the kernel is the Torelli

group, but I am not sure.

Any Ideas/Refs.?

Thanks.
 
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I don't know anything about this subject but this Wikipedia article seems to briefly answer your question.

http://en.wikipedia.org/wiki/Mapping_class_group#Torelli_group

Look at the section on the Torelli group.

I gather from the blurbs in Wikipedia that the mapping class group of an orientable surface acts on the first Z- cohomology of the surface which through the cup product is a linear symplectic manifold. The action preserves the cup product and hence the linear symplectic form that the cup product determines. The reason that the cup product determines a symplectic form is because for a 2 manifold the bilinear form is antisymmetric.

The kernel of the action is called the Torelli group.
 
Last edited:
Thanks, Lavinia:

I just had a dumb confusion; the issue is that every automorphism in Mg gives

rise to an automorphism in homology, and Tg is the kernel of this general assignment

( of the homology functor, I guess) , i.e, the subgroup of automorphisms

that induce the identity map in homology. Sorry, just to make up for my dumb question;

I was confused because I believed since the induced maps (by a diffeo.) are isomorphisms,

that they fixed homology, i.e., were the identity, but this is clearly not the case.

Phew... feels good to get it out of my system. Now, I got to go deal with

ugly level-2 prime congruence subgroups of Sp(2g,Z). Later.
 

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