markosheehan
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is the function x²+3 surjective for real numbers. how do you test for surjectivity in general?
The function f(x) = x² + 3 is not surjective for real numbers because it has a global minimum at y = 3. This means that there are no real numbers x that can produce output values less than 3. To determine surjectivity, one must check if every element in the codomain Y can be achieved by some input from the domain X. In this case, since the function cannot output values below 3, it fails the surjectivity test.
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markosheehan said:is the function x²+3 surjective for real numbers. how do you test for surjectivity in general?
This should say $X\subseteq\mathbb{R}$ instead of $X\in\mathbb{R}$. Also, $R$ in $f:R \rightarrow R$ should probably be $\mathbb{R}$, just like in the first occurrence.Jameson said:Let's say a function $f$ maps some $X \in \mathbb{R}$ to $Y \in \mathbb{R}$. You might write that like $f: X \rightarrow Y|X,Y \in \mathbb{R}$ or maybe just $f:R \rightarrow R$.
Evgeny.Makarov said:This should say $X\subseteq\mathbb{R}$ instead of $X\in\mathbb{R}$. Also, $R$ in $f:R \rightarrow R$ should probably be $\mathbb{R}$, just like in the first occurrence.