Swinging Angle = 30° Swinging on a Rope: How Far Does He Go?

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SUMMARY

The discussion centers on calculating the horizontal distance a man swings from a 15 m high cliff using a 12 m long rope, releasing at a 30° angle from the horizontal. The total swing angle is 150°. The key to solving this problem involves applying the principles of circular motion and conservation of energy to determine the launch speed at the point of release.

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This discussion is beneficial for physics students, educators, and anyone interested in solving problems related to mechanics, particularly those involving pendulum motion and projectile trajectories.

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Homework Statement



A man is trying to swing from a 15 m high cliff on a 12 m long rope. (the rope is horizontal at the start) He let's go when the rope is 30° degrees from the horizontal of the other side. (totaled swung angle is 150°.

How far does he go from the cliff?

Homework Equations


I suppose you would use a circle tangentle speed formula, not too sure.



The Attempt at a Solution



The first part of the problem to calculate the speed of of the launch is where i am having trouble.

___& --------------O
|
|
| *X* is where here he let's go X (30°)
|________________________________________________x__________x_____x_ Where
does he land, how far from the cliff.

Circle Radius = r = 12 m
 
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What conservation laws might help?
 

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