Symmetric functions/odd even or neither

  • Thread starter Thread starter schlynn
  • Start date Start date
  • Tags Tags
    even Symmetric
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 4K views
schlynn
Messages
88
Reaction score
0

Homework Statement


I am supposed to find out if this function is symmetric with reference to the y-axis or reference to the origin.
The function is
F(x)=4x^2/(x^3+x)

Homework Equations



These are how to know if even or odd
A(-x)^even power = ax^even power
A(-x)^odd power = -ax^odd power

The Attempt at a Solution


I think that to solve these u change x to -x in the function right? So I got...
F(-x)=4-x^2/(-x^3-x)
To
F(-x)=4+x/(-x-x)
To
F(-x)=4+x/-2x
To
F(-x)=2+x/-x
To
-2

But now what, how do I tell if it's odd even or neither?? Did I even do the math right?
 
Last edited:
Physics news on Phys.org
schlynn said:

Homework Statement


I am supposed to find out if this function is symmetric with reference to the y-axis or reference to the origin.
The function is
F(x)=4x^2/(x^3+x)

Homework Equations



These are how to know if even or odd
A(-x)^even power = ax^even power
A(-x)^odd power = -ax^odd power
These equations aren't what you use to determine the evenness or oddness of a function.
If f(-x) = f(x) for all x in the domain of f, f is an even function.
If f(-x) = -f(x) for all x in the domain of f, f is an odd function.
schlynn said:

The Attempt at a Solution


I think that to solve these u change x to -x in the function right? So I got...
F(-x)=4-x^2/(-x^3-x)
No, you need some parentheses here.
F(-x) = 4(-x)^2/((-x)^3 + (-x))
= 4x^2/(-x^3 - x)
= -(4x^2)/(x^3 + x)
= ?
schlynn said:
To
F(-x)=4+x/(-x-x)
To
F(-x)=4+x/-2x
To
F(-x)=2+x/-x
To
-2
What are you doing here? You can't get the first of the four lines from what you started with, and the third line doesn't follow from the second, and the fourth doesn't follow from the third.
schlynn said:
But now what, how do I tell if it's odd even or neither?? Did I even do the math right?
 
In general, a function is Even if
[tex]F(x) = F(-x)[/tex]
and a function is Odd if
[tex]F(x) = -F(-x)[/tex]

So consider in your case
[tex]F(x) = -\frac{x^2}{x^3+x}[/tex]

Look now at [tex]F(-x)[/tex]:

[tex]F(-x) = -\frac{(-x)^2}{(-x)^3+(-x)}[/tex]
[tex]= -\frac{x^2}{-x^3-x}[/tex]
[tex]= \frac{x^2}{x^3+x}[/tex]
[tex]= -F(x)[/tex]

So your function is Odd.

Another approach is to treat it as a product or quotient of even or odd functions

Odd function * Odd function = Even function
Even * Even = Even
Even * Odd = Odd
Odd * Even = Odd

Likewise
Odd / Odd = Even
Even / Even = Even
Even / Odd = Odd (this is your case)
Odd / Even = Odd