Symplectic Condition For Canonical Transformation

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SUMMARY

The symplectic condition for a transformation to be canonical is defined as MJM' = J, where M' is the transpose of M, as outlined in Chapter 9 of "Classical Mechanics" by Goldstein. This condition is not universally applicable to all matrices; specifically, only symplectic matrices, which belong to the group SL(2, ℝ), satisfy the condition with a determinant of 1. The discussion clarifies that while various matrices may satisfy the equation, they do not necessarily represent canonical transformations unless they meet the symplectic criteria. The 2D phase space example illustrates that the determinant condition is essential for confirming symplecticity.

PREREQUISITES
  • Understanding of symplectic geometry
  • Familiarity with canonical transformations
  • Knowledge of matrix operations and properties
  • Basic concepts of phase space in classical mechanics
NEXT STEPS
  • Study the properties of the symplectic group SL(2, ℝ)
  • Learn about Poisson brackets and their role in canonical transformations
  • Explore higher-dimensional symplectic matrices and their applications
  • Review matrix determinants and their significance in linear algebra
USEFUL FOR

Students and professionals in classical mechanics, mathematicians focusing on symplectic geometry, and physicists interested in canonical transformations will benefit from this discussion.

CassiopeiaA
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I am reading Chapter 9 of Classical Mech by Goldstein.The symplectic condition for a transformation to be canonical is given as MJM' = J, where M' is transpose of M. I understood the derivation given in the book. But my question is : isn't this condition true for any matrix M? That is it doesn't matter whether we are talking about canonical transformation or not, any real matrix will satisfy the condition with the given J. And if so then how do I check if the given transformation is canonical without using the Poisson Bracket condition?
 
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How do you come to that conclusion? Why don't you check the condition for the most simple case of a 2D phase space?
 
vanhees71 said:
How do you come to that conclusion? Why don't you check the condition for the most simple case of a 2D phase space?
I took 2X2, 3X3 and 4X4 matrices with unknown variables and did the operation on them. All of them satisfied the condition. I also did a small proof for NXN matrix, that the above condition is true for any matrix.
 
Then there must be some misunderstanding on your part. Let's check the 2D case. By definition
$$J=\begin{pmatrix} 0 & 1 \\ -1 & 0 \end{pmatrix}.$$
Now let ##M \in \text{Sp}(2)##, i.e.,
$$M J M^T=J.$$
Set
$$M=\begin{pmatrix} a & b \\ c & d \end{pmatrix}.$$
Then the condition for symplecticity is
$$ad-bc=\det{M} \stackrel{!}{=}1.$$
This means for the 2D case the symplectic matrices are the ##\mathrm{SL}(2,\mathbb{R})## matrices, i.e., the matrices with determinant 1, and not all real ##2 \times 2## matrices fulfill this condition.

For more details see

https://en.wikipedia.org/wiki/Symplectic_group
 

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