MHB System of Equations: Find Triples $(x,y,z)$

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SUMMARY

The forum discussion focuses on solving the system of equations defined by $x^3=3x-12y+50$, $y^3=12y+3z-2$, and $z^3=27z+27x$. Participants utilized algebraic manipulation and substitution techniques to derive potential solutions for the triples $(x,y,z)$. The final conclusion indicates that the solutions include specific real number combinations, which were verified through substitution back into the original equations.

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Find all triples $(x,\,y,\,z)$ of real numbers that satisfy the system of equations

$x^3=3x-12y+50\\y^3=12y+3z-2\\z^3=27z+27x$
 
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Observe the following identities:
$x^3-3x-2=(x-2)(x+1)^2\\y^3-12y-16=(y-4)(y+2)^2\\z^3-27z-54=(z-6)(z+3)^3$

Suppose $x>2$, we then have

$-12y+50=x^3-3x>2\implies y<4$

$z^3-27z=27x>54 \implies z>6$

$y^3-12y=3z-2>16 \implies y>4$

which leads to a contradiction.

Now, assume $x<2$, we then have

$-12y+50=x^3-3x<2 \implies y>4$

$3z-2=y^3-12y>16 \implies z>6$

But this leads to

$27x=z^3-27z>54$ which is impossible.

THus, $x=2$ and that gives the only solution set $(x,\,y,\,z)=(2,\,4,\,6)$.
 

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