- #1
solakis1
- 422
- 0
solve the following system:
\(\displaystyle x^2 +xy +y^2=37\)
\(\displaystyle x^2+xz+z^2=28\)
\(\displaystyle y^2+yz+z^2=19\)
\(\displaystyle x^2 +xy +y^2=37\)
\(\displaystyle x^2+xz+z^2=28\)
\(\displaystyle y^2+yz+z^2=19\)