Tangential and Normal of a rotating mass

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nysnacc
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Homework Statement


14.76.PNG


Homework Equations


at = Rα
an = V2/ R = Rω2

Vt
Vn =0

The Attempt at a Solution


I found at=0
an=5.66 m/s
vt=3.364
vn=0


So v = vt = 3.364 m/s[/B]
Correct?
 
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oh yes, a in m/s^2 typo :)

for vt, first, I need ω, which is found from an = v^2/R where R is L sinθ

SO, v = sqrt (an*R) = sqrt (5.66*4sin30°) = 3.36 m/s
 
nysnacc said:
SO, v = sqrt (an*R) = sqrt (5.66*4sin30°) = 3.36 m/s
What are the units associated with that 4 (highlighted in red)?
 
4 in meter, which is the length of L
 
the question is modified, it was shown 4 ft but actually it should be in meter.
 
nysnacc said:
4 in meter, which is the length of L
nysnacc said:
the question is modified, it was shown 4 ft but actually it should be in meter.
Ah. It would have been nice to have been made aware of this detail in the problem statement o_O

In that case your tangential velocity looks okay.
 
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Hopefully I wouldn't make the same mistake next time, thanks for pointing out :)

And at = 0 (rotating in constant angular speed), vn = 0 (constant radius R) correct?
 
nysnacc said:
And at = 0 (rotating in constant angular speed), vn = 0 (constant radius R) correct?
Yes.
 
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gneill said:
Yes.
Great! Actually these questions appeared on my midterm today, and these were my answers