Tangential and radial particle acceleration

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The discussion revolves around determining the x and y coordinates of a particle moving in a circular path given its velocity and acceleration. The particle's velocity is 4.6j m/s, indicating it is moving vertically, while the acceleration is (2.3i - 2.1j) m/s^2. Participants clarify that the radial acceleration formula ar = -v^2/r requires the correct interpretation of the total acceleration, emphasizing that the y-coordinate must be zero for the velocity to remain tangential to the circle. The confusion arises from the calculation of the radius and the role of the acceleration components. Ultimately, the consensus is that the y-coordinate is zero to align with the particle's motion.
Why-not2007
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Homework Statement


A particle moves in the xy plane in a circle centered origin. At a certain instant the velocity and acceleration of the particle are 4.6j m/s and (2.3i - 2.1j) m/s^2. What are the x and y coordinates of the particle at this moment


Homework Equations


ar=-v^2/r


The Attempt at a Solution


I took the magnitude of the radial acceleration and got 3.11 m/s^2 and plugged it into the equation. I got -6.8 for my radius and was told that was the wrong answer for the x coordinate. Then I tried plugging in 2.3 for the radial acceleration and got -9.2 for my radius. Does the -2.1j m/s^2 not play a factor in this problem? I got x=-9.2, but I don't know how to solve for the y component of the problem.
 
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Why-not2007 said:
I took the magnitude of the radial acceleration and got 3.11 m/s^2 and plugged it into the equation.
How did you get this? Are you assuming that the particle is moving with a constant speed? (You are given the total acceleration, not the radial acceleration.)
I got -6.8 for my radius and was told that was the wrong answer for the x coordinate. Then I tried plugging in 2.3 for the radial acceleration and got -9.2 for my radius. Does the -2.1j m/s^2 not play a factor in this problem? I got x=-9.2, but I don't know how to solve for the y component of the problem.
The velocity should tell you the y-coordinate, since it moves in a circle.
 
Why-not2007 said:

Homework Statement


A particle moves in the xy plane in a circle centered origin. At a certain instant the velocity and acceleration of the particle are 4.6j m/s and (2.3i - 2.1j) m/s^2. What are the x and y coordinates of the particle at this moment


Homework Equations


ar=-v^2/r


The Attempt at a Solution


I took the magnitude of the radial acceleration and got 3.11 m/s^2 and plugged it into the equation. I got -6.8 for my radius and was told that was the wrong answer for the x coordinate. Then I tried plugging in 2.3 for the radial acceleration and got -9.2 for my radius. Does the -2.1j m/s^2 not play a factor in this problem? I got x=-9.2, but I don't know how to solve for the y component of the problem.
The velocity is given as being in the 'j' direction only. That should give you a hint on the possible location of the y coordinate. Your value of the centripetal acceleration that you must use depends on the value of the y coordinate you must find first.
 
The y coordinate equal 0?
 
Why-not2007 said:
The y coordinate equal 0?
Absolutely. That's the only way to make sense of the given velocity, since that velocity must be tangential to the circle at all times.
 
Thanks, I appreciate the help.
 
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