Taylor Series for sin(x) Centered at π/2 with Infinite Radius of Convergence

Click For Summary
SUMMARY

The Taylor series expansion for sin(x) centered at π/2 is accurately represented by the formula: ∑((-1)^n (x-π/2)^(2n)/(2n)!, n=0,∞). This series has an infinite radius of convergence, allowing it to converge for all real values of x. The derivation and application of this series are essential for understanding the behavior of the sine function near π/2.

PREREQUISITES
  • Understanding of Taylor series and their applications
  • Familiarity with trigonometric functions, specifically sin(x)
  • Knowledge of convergence criteria for infinite series
  • Basic calculus, including factorial notation and limits
NEXT STEPS
  • Study the derivation of Taylor series for other trigonometric functions
  • Explore the concept of radius of convergence in more detail
  • Learn about the applications of Taylor series in numerical methods
  • Investigate the relationship between Taylor series and Maclaurin series
USEFUL FOR

Mathematicians, physics students, and anyone interested in advanced calculus or numerical analysis will benefit from this discussion on the Taylor series for sin(x) centered at π/2.

nameVoid
Messages
238
Reaction score
0
f(x)=sinx
taylor series centered at pi/2

sum((-1)^n (x-pi/2)^(2n)/(2n)! , n=0,infty ) with radius of convergence infty
 
Physics news on Phys.org
\sum\limits_{n=0}^{\infty} \left(\frac{(-1)^n(x-\frac{\pi}{2})^{2n}}{(2n)!} \right) is correct
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
10
Views
2K