Tension and torque of a suspended scaffold

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The discussion focuses on calculating the tension in the left rope of a suspended scaffold with a man standing on it. The man weighs 65.2 kg, the scaffold weighs 22.7 kg, and the total length of the scaffold is 2.4 m. The tension in the right rope (Tr) was calculated to be 538 N using the equation 65.2(9.8)(1.6) + (22.7)(9.8)(1.2) - Tr(2.4) = 0. To find the tension in the left rope (Tl), participants suggest summing moments about the left end and checking the forces in the vertical direction to ensure equilibrium.

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A man of mass 65.2 kg stands on a scaffold supported by a vertical rope at each end. The scaffold has a mass of 22.7 kg and is 2.4 m long. Suppose the man stands to the right from the middle of the scaffold that is a distance one sixth of the length of the scaffold. What is the tension in the left rope?

I already found the tension in the right rope, by doing...

65.2(9.8)(1.6) + (22.7)(9.8)(1.2) - Tr(2.4) = 0
and solving for Tr i got 538 N.

However I am unsure of how to get Tl ?
 
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Why you did well summing moments about the left end; now trying summing moments about the right end.:smile:

Then check your work by summing forces in the y direction...If you got the correct values of the left end and right end tensions, all your forces should sum to zero.
 

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