Tension & Circular Motion Question - Looking for speed

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Homework Help Overview

The discussion revolves around a problem related to tension and circular motion, specifically focusing on the relationship between speed and radius in a scenario involving a cable. Participants are examining the interpretation of the problem and the calculations involved.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants are questioning the correctness of their interpretations and calculations, particularly regarding the use of radians versus degrees in their calculations. There is also discussion about handling negative signs in calculations and the implications of using different values for gravitational acceleration.

Discussion Status

The discussion is active, with participants providing feedback on each other's interpretations and calculations. Some have identified potential errors in numerical calculations and the use of units, while others are exploring the implications of assumptions made in the problem setup.

Contextual Notes

There is mention of a diagram and specific angles, which may not be fully detailed in the posts. Participants are also reflecting on common mistakes, such as calculator settings, which could affect their results.

dcmf
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Homework Statement
A person sitting in a chair (combined mass 80 kg) is attached to a 6.0-m-long cable. The person moves in a horizontal circle. The cable angle θ is 62 degrees below the horizontal. What is the person's speed? Note: The radius of the circle is not 6.0 m.
Relevant Equations
a = v^2/r
I have attached a screenshot of my rough work. First of all, is my interpretation of the question correct? Please see the diagram in purple. To me, this makes sense because a=v^2/r is the only equation from my coursework that seems to relates radius (which you can find from the length of the cable) and speed.
1707605967159.png
 
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Hello @dcmf,
:welcome:

dcmf said:
is my interpretation of the question correct?
I guess so. Apparently the person is not in a wheelchair going around slowly ?

What do you do with the minus sign ?
And when I do the calculation, I get a different answer.

##\ ##
 
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Welcome, @dcmf !

All the steps seem to be correct, but the final numerical calculation is incorrect.
As Tx and Ty are directly proportional to the horizontal and vertical accelerations respectively, you could have used those values directly.

##tan~28=ac/g##
 
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Hi all, thank you for your replies. When you both said you're getting a different number doing the same calculation, I realized my calculator has been in radians and not degrees this entire time 🤡

Thanks for your patience and help :')
 
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dcmf said:
my calculator has been in radians and not degrees
Happens often (and to all of us :wink:). Reason the more to check things, e.g. ##\sin(28^\circ)\approx 0.5## -- so you learn to smell a rat if you get ##0.27##

##\ ##
 
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Screen Shot 2024-02-10 at 7.11.41 PM.png

How did you handle the negative sign under the radical? You can't simply ignore it because it shouldn't be there. Think about this because you might will get into trouble if you replace ##g## with ##-9.80~\text{m/s}^2## indiscriminately.
 
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