No, it's not fiction, it's friction. The bus is stationary when you board. You are standung, say. When the bus starts, if there were ni friction between your shoes and the bus floor you would remain still, your shoes sliding, until you hit the back of the bus.gracy said:
typo.gracy said:
If you mean #27, yes. So,gracy said:
Yes.haruspex said:
In particular, forward relative to the car. So friction acts the other way, agreed? What, then, is the sum of forces?gracy said:
Yes. What is the relationship between the tension there and the tension at the end attached to the block?gracy said:
Right.gracy said:
As I posted previously, you don't care about the mass of the car or the forces on it because you know exactly how it is moving. Concentrate on the forces on the block and its acceleration.gracy said:
Whether or not it is correct, it is irrelevant. Please just answer my questions in post ##34.gracy said:
Backward.haruspex said:
No.haruspex said:
T-150N =30Kg multiplied by acceleration of the block.haruspex said:
Here I am struggling.haruspex said:
Ok so far.gracy said:
Yes.gracy said:
That cannot be string, or the pulley would fall down. Must be a rod.gracy said:
Same as distance covered by small block.haruspex said:
No. Forget the block for the moment, and concentrate on the car, the pulley, the wall, and the length of string from wall to pulley. If the car moves 1m further from the pulley, how much longer is that part of the string?gracy said:
Total length of string - length of the top part of the string ?haruspex said:
No, I'm asking about that top part of the string, the part that runs horizontally from the wall to the pulley.gracy said:
gracy said:Total length of string -(minus) length of the top part of the string .Right?/QUOTE]
