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aeroengphys

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For homework, I was given the following problem:

A .5kg hangs from two strings at the angles shown. The longer string is .5m long.

(a) Determine the tension in each string.

(see attachment for diagram)Can you tell me how this looks...

1st I broke everything into x and y components (ie Tlx, Tly, Trx, Try) then i did the following:

ΣF=0N

Tlx=Trx

Tlcos(60)=Trcos(25)

Tl=Trcos(25)/cos(60)

ΣF=0N

Tly + Try = 5N

Tlsin(60)+Trsin(25) = 5N

(Trcos25/cos60)*sin60 + Trsin25= 5N

Tr((cos25*sin60)/cos60) + sin25= 5N

Tr = (5N - sin25)/((cos25*sin60)/cos60)

Tl = (2.92N)(cos25)/cos(60)

Hopefully that's right...Thanks in advance for letting me know.

A .5kg hangs from two strings at the angles shown. The longer string is .5m long.

(a) Determine the tension in each string.

(see attachment for diagram)Can you tell me how this looks...

1st I broke everything into x and y components (ie Tlx, Tly, Trx, Try) then i did the following:

__x__ΣF=0N

Tlx=Trx

Tlcos(60)=Trcos(25)

Tl=Trcos(25)/cos(60)

__y__ΣF=0N

Tly + Try = 5N

Tlsin(60)+Trsin(25) = 5N

(Trcos25/cos60)*sin60 + Trsin25= 5N

Tr((cos25*sin60)/cos60) + sin25= 5N

Tr = (5N - sin25)/((cos25*sin60)/cos60)

**Tr = 2.92N**Then...I went back to my x components and plugged in Tr and solved for Tl as shown:Tl = (2.92N)(cos25)/cos(60)

**Tl = 5.29N**Hopefully that's right...Thanks in advance for letting me know.

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