How Do Tensors Function in Geometric Algebra?

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SUMMARY

Tensors function as formulas for converting vectors, with rank-n tensors represented as homogeneous multivectors in Geometric Algebra (GA). A bivector is identified as a rank 2 tensor, while rank 1 tensors correspond to vectors. The discussion highlights the complexity of traditional tensor analysis, which involves Jacobians and transformation laws, contrasting it with the simplicity of GA definitions. The stress-energy tensor is noted for its symmetric representation in GA, although not all tensors have natural representations in this framework.

PREREQUISITES
  • Understanding of Geometric Algebra (GA) principles
  • Familiarity with tensor analysis concepts, including Jacobians and transformation laws
  • Knowledge of vector and multivector relationships
  • Basic grasp of physical concepts such as angular momentum and angular velocity
NEXT STEPS
  • Study the 'Gradient and tensor notes' from the provided GA resource
  • Explore the Lorentz force equation in both GA and index form
  • Investigate the representation of symmetric tensors in Geometric Algebra
  • Examine the relationship between angular momentum and angular velocity in rigid body dynamics
USEFUL FOR

Students and professionals in physics, mathematicians interested in Geometric Algebra, and anyone seeking to deepen their understanding of tensor applications in mechanics and relativity.

mnb96
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Hello,
can anyone explain simply what is a tensor, using the language of Geometric Algebra?
Thanks!
 
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A (rank-n) tensor is just any homogeneous multivector (n-vector).
For example, a bivector is a rank 2 tensor.
 
Wow, that sounds very simple.

However I still have some troubles. If you open any book on tensor analysis, and look for the general definition of a (mixed) tensor of order (m+n), you'll find something pretty obscure (for the beginner) which involves Jacobians, weights, partial derivatives, transformation laws, covariant/contravariant components.

I am really missing how all those "ingredients" can be absorbed into such a simple definition in Geometric Algebra.
 
You can start with understanding rank 1 tensors in terms of vectors (a special case of multivectors). Try:

'Gradient and tensor notes'

in:

http://sites.google.com/site/peeterjoot/math2009/gabook.pdf

I have a lot of other worked examples here:

http://sites.google.com/site/peeterjoot/electrodynamics

that translate to and from tensors and GA (as I am learning both simultaneously). In particular, try taking somerthing like the Lorentz force equation in GA form:

<br /> \dot{p} = q F \cdot v/c<br />

and translate this to index form. That is a good exercise to get some comfort with the index manipulation, and to see how the vector and bivector objects are related to their tensor equivalents.

Also note that GA doesn't neccessarily have a natural representation for any arbitrary tensor. Any completely antisymetric tensor has a blade representation. I'm not so sure that you'd neccessarily find natural representations for symmetric tensors, or more general tensors. The stress energy tensor which is symmetric does happen to have a slick GA representation, but I don't currently have a clue how one would figure out that out without knowing it beforehand (I can't currently follow the derivations I've seen).
 
Hi mnb96! :smile:
mnb96 said:
Hello,
can anyone explain simply what is a tensor, using the language of Geometric Algebra?
Thanks!

A tensor is a formula for converting one vector to another vector.

For example, the https://www.physicsforums.com/library.php?do=view_item&itemid=31" tensor converts the angular velocity vector of a rigid body into the angular momentum vector: Iω = L.

(surprisingly, angular momentum is not generally aligned with rotation. :wink:)
 
Last edited by a moderator:
tiny-tim said:
Hi mnb96! :smile:

(surprisingly, angular momentum is not generally aligned with rotation. :wink:)

That's an interesting statement. Angular momentum is MLT^-1 where velocity is measured in radians per second. This implies rotation. I can see how a particle moving along a curving path (not a circle) has an angular velocity at every point but is not in a rotary path around some point. Is this what you mean? (Strictly speaking the particle is in a rotary path around some point, but only instantaneously depending on the trajectory.)
 
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SW VandeCarr said:
That's an interesting statement. Angular momentum is MLT^-1 where velocity is measured in radians per second. This implies rotation. I can see how a particle moving along a curving path (not a circle) has an angular velocity at every point but is not in a rotary path around some point. Is this what you mean?

?? :confused:

I mean that the angular momentum vector of a rigid body is not generally in the same direction as its angular velocity vector.
 
tiny-tim said:
?? :confused:

I mean that the angular momentum vector of a rigid body is not generally in the same direction as its angular velocity vector.

I don't think that's true in a gravitational field where a massive body is following a geodesic.
 
Last edited:

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