A small body of mass m located near the Earth’s surface falls from rest in the Earth's gravitational field. Acting on the body is a resistive force of magnitude kmv, where k is a constant and v is the speed of the body. a) Write the differential equation that represents Newton's second law for this situation. my answer: F = ma a = dv/dt F = mg - kmv ma = mg - kmv a = g - kv dv/dt = g - kv I'm pretty sure I got this one right. b) Determine the terminal speed vT of the body. F = 0 g - kv = 0 g = kv vT = g / k I think I got this one right too. c) Integrate the differential equation once to obtain an expression for the speed v as a function of time t. Use the condition that v = 0 when t= 0. What I did so far: dv/dt = g - kv dt = dv / (g - kv) So I would integrate dt = dv / (g - kv). The problem is I don't know how. Can someone please explain how to do this kind of integration, why I would do it that way?