High School Are f(x) and f(-x) Equivalent Functions?

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The discussion centers on whether f(x) and f(-x) are equivalent functions. It is clarified that while f(x) and f(-x) can yield the same output for specific inputs, they are fundamentally different functions, as demonstrated by their differing outputs for certain values. The functions are mirror images across the y-axis, meaning that f(-x) reflects f(x) when graphed. The conversation also touches on the concept of function composition, illustrating how applying different functions sequentially can lead to different results. Ultimately, f(x) and f(-x) are not equivalent, but they exhibit a symmetrical relationship.
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Hi.
If I have a function for example f( x ) = x2 + x then to obtain f( -x) I just put (-x) in place of the x in f(x)
so I get f( -x) = x2 - x
Am I right so far ?
So f(x) and f(-x) look like different functions but if you put a negative number in f(-x) it flips the -x back to +x so are f(x) and f(-x) are equivalent ?
But if I put sin(x) as the argument I get a totally different function

Thanks
 
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dyn said:
Hi.
If I have a function for example f( x ) = x2 + x then to obtain f( -x) I just put (-x) in place of the x in f(x)
so I get f( -x) = x2 - x
Am I right so far ?
Yes
So f(x) and f(-x) look like different functions
Yes. In fact, they are different functions. Which suggests that it is not a good idea to call them both by the same name. So invent a different name. Let g(x) = f(-x).

Now f(x) is a different function from g(x). In particular, f(1) = 12 + 1 = 2 and g(1) = f(-1) = (-1)2 + (-1) = 0.
but if you put a negative number in f(-x) it flips the -x back to +x so are f(x) and f(-x) are equivalent ?
Yes, if you put a negative number into g(x) and the corresponding positive number into f(x) you get the same result out. The graphs of the two functions are mirror images of each other, reflected across the y axis.

g(x) = f(-x) and f(-x) = g(x).
But if I put sin(x) as the argument I get a totally different function
You lost me. What function are you getting when you do what to what and how is it different from what?

You may be talking about something called function composition where you apply two functions in sequence to the input argument. So if "-" is the name of the additive inverse function "-"(x) = -x then your original example could be thought of as the composition of f with "-": ##g = f \circ -## or g(x) = f(-x).

And your sin example could be thought of as the composition of f with sin: ##g = f \circ \sin## or ##g(x) = f(\sin x)##
 
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dyn said:
but if you put a negative number in f(-x) it flips the -x back to +x so are f(x) and f(-x) are equivalent ?
They are mirror versions of each other: If you mirror f(x) at the vertical axis you get f(-x). This is a general property of all functions (from real numbers to real numbers).
If f(x)=sin(x), then f(-x)=sin(-x)=-sin(x) which is the sine mirrored at the vertical axis.
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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