The curious case of 50x^2 - 72

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In summary, the conversation discusses the process of factoring a polynomial, specifically 50x^2 - 72. The speaker initially uses the difference of two squares method to get the correct answer of 2(5x - 6)(5x + 6). However, when attempting to solve it using traditional factoring methods, they make a mistake and get an incorrect answer. They also compare it to a similar problem, 4x^2 - 9, where they use the correct method and get the correct answer of (2x - 3)(2x + 3). The conversation concludes with the speaker admitting their mistake and thanking the other participants for their help.
  • #1
Bavariadude
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I chose this subject title to get your attention. :biggrin:

Anyway, I know how to solve it; it's obviously a matter of factoring and the difference of two squares:

50x^2 - 72
2(25x^2 - 36)
2(5x - 6) (5x + 6)

However, when I try to solve it the normal way -- by factoring -- things go wrong:

50x^2 - 72
2(25x^2 - 36)
2(25x^2 - 450x + 450x - 36)

Here is where things get messy. I can't seem to factor it all the way down to 2(5x - 6) (5x + 6):

2(5x[5x - 90] +3[150x - 12])

If I go for the greatest common factor, I get this:

2(25x[x - 18] +6[75x - 6])

And if I pick a suitable factor, I get this:

2(5x[5x - 90] +6[75x - 6])

In the last one, I was able to form (5x +6), but here's where things come to a dead end.

What confuses me is that if we take a similar problem that can be solved smoothly through the difference of two squares, like, 4x^2 - 9 -- which immediately becomes (2x - 3) (2x + 3) -- it can still be solved through plain factoring:

4x^2 - 9
4x^2 - 6x + 6x - 9
2x(2x - 3) +3(2x - 3)
(2x - 3) (2x + 3)

So why is the straightforward factoring method succeeding with 4x^2 - 9, but failing with 50x^2 - 72?
 
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  • #2
When you get down to the answer of
2(5x - 6) (5x + 6)
None of these factors are being added, they are being multiplied.
So when you go down the path of
2(5x[5x - 90] +3[150x - 12])
You should now be expecting an answer to have various factors being added or subtracted, which is expected.

Not all polynomials can be factored the same way. In fact, most of my math experiences there are multiple methods to solve problems. You just need to be able to look at the problem initially and try to deduce the easiest method of factorization.
 
  • #3
Bavariadude said:
I chose this subject title to get your attention. :biggrin:

Anyway, I know how to solve it; it's obviously a matter of factoring and the difference of two squares:

50x^2 - 72
2(25x^2 - 36)
2(5x - 6) (5x + 6)

However, when I try to solve it the normal way -- by factoring -- things go wrong:

50x^2 - 72
2(25x^2 - 36)
2(25x^2 - 450x + 450x - 36)
Why are you adding and subtracting 450x? That is, of course, 25(36) but in the example you have below, 4x^2 - 9, you add and subtract 6= 2(3) not 4(9). Since 25= 5^2 and 36= 6^3, following that same pattern, you should add and subtract 5(6)x= 30x:

2(25x^2- 30x+ 30x- 36)= 2(5x(5x- 6)+ 6(5x- 6))= 2(5x-6)(5x+6), exactly what you got before.
Actually, your first method, recognizing that (25x^2- 36) is the difference of two squares, is factoring. What you do in the second method, adding and subtracting a number times x, is a rather unusual method that only works in special situations and is NOT "the normal way".

Here is where things get messy. I can't seem to factor it all the way down to 2(5x - 6) (5x + 6):

2(5x[5x - 90] +3[150x - 12])

If I go for the greatest common factor, I get this:

2(25x[x - 18] +6[75x - 6])

And if I pick a suitable factor, I get this:

2(5x[5x - 90] +6[75x - 6])

In the last one, I was able to form (5x +6), but here's where things come to a dead end.

What confuses me is that if we take a similar problem that can be solved smoothly through the difference of two squares, like, 4x^2 - 9 -- which immediately becomes (2x - 3) (2x + 3) -- it can still be solved through plain factoring:

4x^2 - 9
4x^2 - 6x + 6x - 9
2x(2x - 3) +3(2x - 3)
(2x - 3) (2x + 3)

So why is the straightforward factoring method succeeding with 4x^2 - 9, but failing with 50x^2 - 72?
It succeeded in the second problem but not the first because you did it RIGHT in the second problem but not the first!
 
  • #4
Whoa! You're right HallsofIvy! All this time I've actually been dealing with 450 from 900/2 instead of 30, the square root of 900! I'm so embarrassed at this ridiculous mistake! :blushing:

What you do in the second method, adding and subtracting a number times x, is a rather unusual method that only works in special situations and is NOT "the normal way".

I have to disagree there. It is not unusual to treat 50x^2 - 72 as ax^2 - bx - c, with b = 0. In the second example, I have gone with 4(-9). It brought me to -36, and the two numbers that add up to 0 and multiply to give -36 are -6 and +6. I've tried it several times and it worked. The only reason I've messed up with 50x^2 - 72 is because I've mistakenly went with -450 and +450 (which really do add up to 0, but multiply to -202500) instead of -30 and +30, which add up to 0 and multiply to -900, the product of 25(-36). I rushed and failed to notice the error.

Anyway, thank you both for your assistance. I've learned my lesson. Next time, I'll be very, very careful. :smile:
 

1. What is the significance of the number 50 in the equation 50x^2 - 72?

The number 50 is the coefficient of the x^2 term in the equation. This means that the quadratic term is being multiplied by 50, which affects the shape and position of the graph.

2. How many solutions does the equation 50x^2 - 72 = 0 have?

The number of solutions for this equation depends on the value of the discriminant, which is 64. Since the discriminant is greater than 0, there are two real solutions.

3. Can the equation 50x^2 - 72 = 0 be solved without using the quadratic formula?

Yes, this equation can also be solved by factoring. In this case, the equation can be factored into (5x + 6)(10x - 12) = 0, giving the solutions x = -6/5 and x = 12/10, which can be simplified to x = -6/5 and x = 6/5.

4. What is the vertex form of the equation 50x^2 - 72 = 0?

The vertex form of the equation is y = 50(x - 0)^2 - 72. This form can be used to easily identify the vertex of the parabola, which is (0, -72).

5. How does changing the value of the constant term in the equation 50x^2 - 72 = 0 affect the graph?

The constant term, in this case -72, is the y-intercept of the graph and affects the vertical position of the parabola. Changing the value of the constant term will shift the graph up or down on the y-axis.

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