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The Deuterium Nucleus Spin Question

  1. Jan 27, 2006 #1
    Ok, I have a question that's really irritating me.

    I am trying to explain why deuterium's nucleus has a spin of 1.

    By the addition of angular mometum of the individual nucleons (1 proton and 1 neutron) that make up the deuterium nucleus, there are three possible choices (from the triangle inequality theorem): 0, 1/2, and 1.

    I can rule out 1/2 because that would imply that the z-component is either -1/2 or +1/2... something I can't do by adding the z-components of the angular momentum of the individual nucleons (you can only get 0 or 1).

    But I can't seem to rule out the possibility of spin-0 deuterium nucleus.

    Any thoughts?
  2. jcsd
  3. Jan 28, 2006 #2

    Meir Achuz

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    It de[emds on the properties of the nuclear force. The n-p attraction is slightly stronger in the spin 1 state than in the spin zero state. The theoretical reason for this has to do with the exchange of pions between the n and the p.
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