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etotheipi

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If the nuclear spin quantum number of a particular type of nucleus is ##I##, then the ##z##-component of spin can take values ##m_I = -I, \dots, I##, and since the energy of a dipole is ##E = - \vec{\mu} \cdot \vec{B} = - \gamma m_I \hbar B_0## (with ##\vec{B} = B_0 \hat{z}##), you end up with ##2I+1## nuclear energy levels.

If ##I =1 ##, for instance, the nucleus will have 3 energy levels, and there will be two possible transitions each of magnitude ##\Delta E_1 = \gamma \hbar B_0## and ##\Delta E_2 = 2\gamma \hbar B_0##. That suggests that you'd obtain two peaks for that nucleus in the spectrum. For even larger values of ##I##, it seems that the spectrum would get quite complicated, with multiple peaks for each nucleus even without taking into account coupling.

I know that it's quite common to look at coupling to nuclei with spins greater than ##1/2##, e.g. coupling to deuterium in ##^1\mathrm{H}##-NMR or ##^{13}\mathrm{C}##-NMR, but do chemists also perform e.g. ##^2 \mathrm{H}##-NMR, or more generally ##\mathrm{X}##-NMR where the spin of ##X## is greater than ##1/2##? If so, is most of the analysis done computationally?

If ##I =1 ##, for instance, the nucleus will have 3 energy levels, and there will be two possible transitions each of magnitude ##\Delta E_1 = \gamma \hbar B_0## and ##\Delta E_2 = 2\gamma \hbar B_0##. That suggests that you'd obtain two peaks for that nucleus in the spectrum. For even larger values of ##I##, it seems that the spectrum would get quite complicated, with multiple peaks for each nucleus even without taking into account coupling.

I know that it's quite common to look at coupling to nuclei with spins greater than ##1/2##, e.g. coupling to deuterium in ##^1\mathrm{H}##-NMR or ##^{13}\mathrm{C}##-NMR, but do chemists also perform e.g. ##^2 \mathrm{H}##-NMR, or more generally ##\mathrm{X}##-NMR where the spin of ##X## is greater than ##1/2##? If so, is most of the analysis done computationally?

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