The 'i' in the momentum operator

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    Momentum Operator
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Discussion Overview

The discussion centers around the role of the imaginary unit 'i' in the momentum operator within quantum mechanics, specifically addressing concerns about the implications of complex expected values of momentum and the Hermitian nature of operators.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • Some participants express concern that the presence of 'i' in the momentum operator might lead to complex expected values of momentum, questioning the physical meaning of such values.
  • Others assert that all operators in quantum mechanics, including the momentum operator, are Hermitian, which guarantees that their eigenvalues are real and thus avoids the issue of complex expected values.
  • It is noted by some that the inclusion of 'i' is necessary to ensure the momentum operator is Hermitian, which is essential for the physical interpretation of the operator.
  • One participant explains that the derivative operator d/dx is not Hermitian on its own, and the addition of '-i' is required to achieve Hermiticity, leading to a cancellation of terms that results in a real operator.
  • Another participant acknowledges that while calculations may initially yield expressions containing 'i', it is possible to eliminate 'i' from expectation values using trigonometric identities, suggesting that any persistent complex terms indicate an algebraic error.

Areas of Agreement / Disagreement

Participants generally agree on the Hermitian nature of the momentum operator and the necessity of 'i' for this property. However, there remains a debate regarding the implications of complex values in calculations and whether they indicate errors or are simply part of the process.

Contextual Notes

Some assumptions about the mathematical properties of operators and the implications of complex numbers in quantum mechanics are not fully explored, leaving room for further discussion on these points.

aspy591
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The momentum operator is -i*h bar * derivative wrt x. But won't this lead sometimes to complex expected values of momentum? What does this mean physically, since complex values can't be measured.
 
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All operators in QM, including this one, are Hermitian. The eigenvalues of a Hermitian operator are real, not complex. (Which is a good thing, as you point out. Complex values would be a problem.)
 
The i is actually needed to make the momentum operator Hermitian!
 
xepma said:
The i is actually needed to make the momentum operator Hermitian!
Exactly! :smile:
 
The operator d/dx is not Hermitian, so you add a -i to it and the i's cancel out to -1 and then the - cancels out to +1
 
aspy591 said:
But won't this lead sometimes to complex expected values of momentum?

Others have given the reasons why the expectation value of p must always be real.

From a practical point of view, when you calculate such an expectation value, you usually get an expression that contains i, to start with. But you can always eliminate i from these expectation values by using identities such as

[tex]\sin x = \frac{1}{2i} \left( e^{ix} - e^{-ix} \right)[/tex]

If you can't, then you've made a mistake in your algebra somewhere. :wink:
 
Last edited:

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