My graphing calculator says this is 0, but I don't really know how obvious that answer is. My problem is that it's my understanding that in order for a limit to exist, then the one sided limit from either side of the point in question must converge to the same value. What exactly is is the limit of sqrt(x) from [tex]0^-[/tex]? If the square root function was plotted in the x-y plane, and then the complex z plane was plotted perpendicular to this plane, then the square root function would shoot off into the x-z plane for negative values of x. The limit from the negative side of 0 is then clearly toward 0*i, while the limit from the positive side is toward 0. Can the limit be interpreted as existing, using this logic? It's kind of a simple question but I hadn't really thought that I needed to question it before until now.