- #1
ahmeeeeeeeeee
- 21
- 0
Hello
how can I find the moment of inertia of a circular sector about the X axis , which the sector is symmetrical about , with -θ down and θ above ?!
I[itex]_{x}[/itex] = ∫y[itex]^{2}[/itex] dA = ∫y[itex]^{2}[/itex] *y *dx
Or =∫∫ y[itex]^{2}[/itex] dy dx
I don't know how to put the limits of integration , I turned it to polar double integral and put the limits of r from zero to R , and limits of θ from -θ to θ and it gave the correct answer but I don't know why :)
how can I find the moment of inertia of a circular sector about the X axis , which the sector is symmetrical about , with -θ down and θ above ?!
I[itex]_{x}[/itex] = ∫y[itex]^{2}[/itex] dA = ∫y[itex]^{2}[/itex] *y *dx
Or =∫∫ y[itex]^{2}[/itex] dy dx
I don't know how to put the limits of integration , I turned it to polar double integral and put the limits of r from zero to R , and limits of θ from -θ to θ and it gave the correct answer but I don't know why :)