I have this crazy idea to make an air hockey table out of some junk laying around the basement. Before I waste my time messing around with an old table and vacuum I figured I would brush up on my basic physics to figure some stuff out. Lets say we want to lift up a lightweight hockey puck. How much are pressure do we need? The surface has 1/16" holes spaced every 1 (in both x and y) The puck has a 2.5" diameter. The puck has a mass of 18 grams, 0.018 kg The force on the puck due to gravity is 0.1764 N => 0.040466 lbf The pressure needed to lift the puck is equal to the force of gravity in lbs / the area of air that hits the puck. The puck will cover 4 holes at once. Each 1/16" hole has an area of 0.003068 in^2. So the puck covers 0.0123 in^2. PSI = 0.040466 / 0.0123 = 3.29 PSI Does that logic make sense?