The quadratic formula and equilibrium problems

Click For Summary

Discussion Overview

The discussion revolves around the use of the quadratic formula in solving equilibrium problems in chemistry. Participants explore the applicability of the quadratic formula versus alternative methods, particularly in scenarios involving equilibrium constants and approximations.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant questions the necessity of always using the quadratic formula for equilibrium problems, suggesting that there may be faster methods available.
  • Another participant asserts that any valid method can be used, including the quadratic equation when applicable.
  • A third participant mentions the possibility of taking approximations if they are available.
  • It is noted that if the equilibrium constant is smaller than 10^-5 or if the percent error is around 5%, certain simplifications may be acceptable, although one participant admits to forgetting how to calculate percent error.
  • There is a suggestion to disregard X in calculations under specific conditions.

Areas of Agreement / Disagreement

Participants express differing views on the necessity and appropriateness of using the quadratic formula in equilibrium problems, indicating that multiple competing approaches exist without a clear consensus.

Contextual Notes

Limitations include the lack of clarity on when to apply approximations and the conditions under which the quadratic formula is deemed necessary or not. There is also an unresolved mention of how to calculate percent error.

soulja101
Messages
61
Reaction score
0
can i always the quadratic forumula when i m doing these types of problems. my teacher said i can but sometimes theirs faster ways to do it
 
Chemistry news on Phys.org
You can use any method that is valid, includig the quadratic equation when it applies.
 
Taking approximation if available
 
if you're equil constant is smaller than 10^-5 or if the percent error is like 5%, then it's ok

i forget how to calculate % error but just stick to 10^-5 and leave X out of your calculations
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
14
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K