The scalar partner of Majorana particle in SUSY

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SUMMARY

The discussion centers on the properties of the right-handed sneutrino as a scalar partner of the Majorana particle in Supersymmetry (SUSY). Participants debate whether the sneutrino can be classified as a real scalar, given its ability to decay into both (s)leptons and anti-(s)leptons, and its self-conjugate nature. The mathematical implications of the number density calculation for scalars are highlighted, emphasizing that a real scalar cannot possess a non-zero number density. The conversation concludes with a recommendation to review the Klein-Gordon equation for further clarity.

PREREQUISITES
  • Understanding of Supersymmetry (SUSY) concepts
  • Familiarity with Majorana particles and their properties
  • Knowledge of scalar fields and their mathematical representations
  • Basic grasp of the Klein-Gordon equation and its implications
NEXT STEPS
  • Study the properties of right-handed sneutrinos in SUSY models
  • Explore the mathematical framework of Majorana particles
  • Investigate the implications of the Klein-Gordon equation on scalar fields
  • Learn about number density and charge density in quantum field theory
USEFUL FOR

Particle physicists, theoretical physicists, and students studying Supersymmetry and quantum field theory will benefit from this discussion.

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For example, the right-handed sneutrino. It can decay into both (s)leptons and anti-(s)leptons, so it is also the anti-particle of itself. I wonder how it looks like mathematically. If it is the same as normal scalar field, we can still distinguish its anti-particle (the complex conjugate)...
 
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I don't understand. νR is just a single state. So wouldn't its superpartner be a single state also, i.e. a real scalar?
 
Bill_K said:
I don't understand. νR is just a single state. So wouldn't its superpartner be a single state also, i.e. a real scalar?

I don't think it can be a real scalar. When we calculate the number density of the scalar n = -i(\phi\dot\phi^*-\dot\phi\phi^*), a real scalar cannot have a non-zero number density.

Let me rephrase this question: Think about the plane wave solution of this scalar \phi=Ae^{-i\rm{px}}. So its anti-particle \phi=Ae^{i\rm{px}} cannot be itself, unless it is real. But in this case, it cannot have a number density.
 
What you're calling the number density is actually the charge density. Better read up on the Klein-Gordon equation!
 

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