Theoretical Yield in Multi-Step Synthesis

[Soaring Crane]

Homework Statement

Exactly how do you find the theoretical yield of methyl m-nitrobenzoate from 10.0 g of benzoic acid?

Homework Equations

1) Ph-COOH + CH3OH + H2SO4 --> Ph-COOCH3
2) Ph-COOCH3 + HNO3 + H2SO4 --> methyl m-nitrobenzoate

The Attempt at a Solution

10.0 g benzoic acid*(1 mol benzoic acid/122.122 g benzoic acid)*(1 mol methyl benzoate/1 mol benzoic acid)*(136.149 g methyl benzoate/1 mol methyl benzoate) = 11.15 g methyl benzoate from FIRST STEP as theoretical yield

11.15 g methyl benzoate*(1 mol methyl benzoate/136.149 g methyl benzoate)*(1 mol methyl m-nitrobenzoate/1 mol methyl benzoate)*(181.147 g methyl m-nitrobenzoate/1 mol methyl m nitrobenzoate) = 14.83 g methyl m-nitrobenzoate from 10.0 g benzoic acid as theoretical yield?

Thanks.

 

[chemisttree]

That looks good if the formula wts. you give are accurate. I didn't check.
Also, you could have just multiplied the number of moles of benzoic acid by the formula wt. of m-nitromethylbenzoate.