1. The problem statement, all variables and given/known data Exactly how do you find the theoretical yield of methyl m-nitrobenzoate from 10.0 g of benzoic acid? 2. Relevant equations 1) Ph-COOH + CH3OH + H2SO4 --> Ph-COOCH3 2) Ph-COOCH3 + HNO3 + H2SO4 --> methyl m-nitrobenzoate 3. The attempt at a solution 10.0 g benzoic acid*(1 mol benzoic acid/122.122 g benzoic acid)*(1 mol methyl benzoate/1 mol benzoic acid)*(136.149 g methyl benzoate/1 mol methyl benzoate) = 11.15 g methyl benzoate from FIRST STEP as theoretical yield 11.15 g methyl benzoate*(1 mol methyl benzoate/136.149 g methyl benzoate)*(1 mol methyl m-nitrobenzoate/1 mol methyl benzoate)*(181.147 g methyl m-nitrobenzoate/1 mol methyl m nitrobenzoate) = 14.83 g methyl m-nitrobenzoate from 10.0 g benzoic acid as theoretical yield? Thanks.