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Theoretical Yield in Multi-Step Synthesis

  1. Jul 17, 2007 #1
    1. The problem statement, all variables and given/known data

    Exactly how do you find the theoretical yield of methyl m-nitrobenzoate from 10.0 g of benzoic acid?

    2. Relevant equations

    1) Ph-COOH + CH3OH + H2SO4 --> Ph-COOCH3
    2) Ph-COOCH3 + HNO3 + H2SO4 --> methyl m-nitrobenzoate

    3. The attempt at a solution

    10.0 g benzoic acid*(1 mol benzoic acid/122.122 g benzoic acid)*(1 mol methyl benzoate/1 mol benzoic acid)*(136.149 g methyl benzoate/1 mol methyl benzoate) = 11.15 g methyl benzoate from FIRST STEP as theoretical yield

    11.15 g methyl benzoate*(1 mol methyl benzoate/136.149 g methyl benzoate)*(1 mol methyl m-nitrobenzoate/1 mol methyl benzoate)*(181.147 g methyl m-nitrobenzoate/1 mol methyl m nitrobenzoate) = 14.83 g methyl m-nitrobenzoate from 10.0 g benzoic acid as theoretical yield?

    Last edited: Jul 17, 2007
  2. jcsd
  3. Jul 18, 2007 #2


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    That looks good if the formula wts. you give are accurate. I didn't check.
    Also, you could have just multiplied the number of moles of benzoic acid by the formula wt. of m-nitromethylbenzoate.
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