There's a chopstick on my hand. I need to find the 'angles'.

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SUMMARY

The discussion focuses on simulating the angular acceleration of a chopstick falling onto a hand, incorporating the effects of the hand's movement. The key takeaway is that the hand exerts a force that influences both linear acceleration and torque, which must be accounted for in the simulation. The torque can be calculated using the equation F = ma, where F is the force exerted by the hand, m is the mass of the chopstick, and a is the hand's acceleration along the specified axis. Additionally, the center of mass of the chopstick must be considered when determining the torque if the pivot point is not at the center.

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Homework Statement


Known:
- Mass of the chopstick
- Gravity

Homework Equations


ed0ec2ed1783f9c2654b4acf7d432bec.png

c22e37af0377d584aea9ff3cfadf7332.png

8fd728988b0b1704566656584a280601.png


So the alpha(angular acceleration) can be found

The Attempt at a Solution


By knowing angular acceleration, I successfully wrote a program that simulate a chopstick falling onto my hand. But all of this is assuming my hand didn't move at all. Currently in my simulation, only the gravitational force affect the angle change (angular acceleration).

My question:
How my hand affect the angular acceleration?
I have these data:
- My hand's acceleration in x, y and z axis.
 
Last edited by a moderator:
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Welcome to PF!

Hi lgmcben! Welcome to PF! :wink:

Your hand will exert a force F, which wiill increase the linear acceleration by F/m, and will also add a torque. :smile:
 


Hi. Thank you for your answer. =)

tiny-tim said:
Hi lgmcben! Welcome to PF! :wink:

Your hand will exert a force F, which wiill increase the linear acceleration by F/m,

I'm sorry I forgot to mention that I want to omit any linear translation in this simulator ^_^; I only need to simulate the angular-related translations.


I have one more question:
tiny-tim said:
and will also add a torque. :smile:

Does this torque equal to
c22e37af0377d584aea9ff3cfadf7332.png

Where
F = ma
and
m = mass of the chopstick
a = acceleration of my hand in x axis? (if x, y and z axis is too much, then let's talk about only x-axis for now)

Thank you again!
 
Last edited by a moderator:
Yes it does equal to the above specified equation. However, you will need to consider torquing about the centre of mass in the chopsticks if the pivot points are anything except the middle of the chopsticks (assuming mass to be equally distributed and the chopsticks to be rectangular prisms)
 

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