1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Therhelp modynamics and the equilibrium constant

  1. Apr 26, 2006 #1
    Therhelp !!!! modynamics and the equilibrium constant

    Thermodynamics and the equilibrium constant

    Okay I have a question about the equation (* means change) (*() means stander condition) so [G=*(G)+RT ln (Keq)] or just equation *(G)= - RT ln(Keq)
    So what dose the (Keq) stander for??? Kc? Kp? Ksp?? Kf or Kd

    Is it always Kc regardless the chemical reaction? (that’s what my prof told me)
    And then use the equation Kp=Kc (RT)^*n to convert K value???

    Or is does Keq depends on the chemical reaction Kc for solution Kp for Gas???(from the text book)

    And can someone please derived the equation [G=*(G)+RT ln (Keq)] for me?
    Where is it come from and why does it makes sense?
  2. jcsd
  3. Apr 27, 2006 #2


    User Avatar
    Science Advisor
    Homework Helper

    The derivation is a bit extensive, and you'll have to cover some ground in Physical Chemistry before you can make sense out of this particular topic.

    The Kc,Kp,Ksp,Kf,Kd are the equilibrium constants with respect to the concentration Kc, and pressure Kp; the rest are specific forms uniquely suited to the reaction dynamics. That is, they be in terms of the concentration or pressure. Ksp is in reference to the solubility, Kf to complex ion formation, Kd to dissociation.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?

Similar Discussions: Therhelp modynamics and the equilibrium constant
  1. Equilibrium constants (Replies: 5)

  2. Equilibrium constant (Replies: 4)

  3. Equilibrium Constant (Replies: 1)