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Ned Taylor

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## Homework Statement

Given the reaction, at equilibrium, it was found that [C] = 0.20 mol/L, [D] = 0.55 mol/L, [A] = 0.30 mol/L and [ B] = 0.48 mol/L. Calculate the value of Keq.

Reaction: C + D <--> A + B

## Homework Equations

K=products/reactants

## The Attempt at a Solution

[/B]

If we assume that C and D are the reactants then the value of Keq would be:

K=A+B/C+D since K= products/reactants

But if we assume that A+B are the reactants than Keq would be;

K=C+D/A+B

Since these give two difference answers( K=1.3 for the first method, and K=.7638) how does one tell what are the products and reactants. Thanks to anyone who can help me with this!

Ned

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