- #1

morrobay

Gold Member

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- 205

Thermal Conductivity , k , for water is .1455 cal/sec/ meter * C ( converted watts to cal/sec)

Q/t = k* A delta T/ d

A= area M

d = thickness of water/ice boundary layer

Suppose I want to calculate time for 100 grams of ice to melt ( 8000 calories absorbed

from surroundings by conduction.

I have delta T and initial surface area of ice/water interface .

Two questions : What would be the boundary layer thickness. d

And in the case that the surface area, A, is decreasing as the ice melts is it correct to

use just the initial surface area in the calculation ?

My reasoning on the area is that it would actually be : Integral A(initial) - A(final) and

A(final ) = 0

Q/t = k* A delta T/ d

A= area M

^{2}d = thickness of water/ice boundary layer

Suppose I want to calculate time for 100 grams of ice to melt ( 8000 calories absorbed

from surroundings by conduction.

I have delta T and initial surface area of ice/water interface .

Two questions : What would be the boundary layer thickness. d

And in the case that the surface area, A, is decreasing as the ice melts is it correct to

use just the initial surface area in the calculation ?

My reasoning on the area is that it would actually be : Integral A(initial) - A(final) and

A(final ) = 0

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