Thermal Properties: Pressure, Volume, Temp question

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SUMMARY

The discussion revolves around calculating the final temperature of air in a Jaguar XK8 convertible's engine cylinder during the compression stroke. The initial conditions include a volume of 499 cm³ at atmospheric pressure (1.01E5 Pa) and a temperature of 27.0°C, while the final conditions are a volume of 46.2 cm³ and a gauge pressure of 2.72E6 Pa. The initial attempt to solve the problem using the ideal gas law equation P1*V1/T1 = P2*V2/T2 was incorrect due to the temperature needing to be converted to Kelvin. The correct approach involves using the isentropic process equations, specifically the relationship pv^gamma = constant, where gamma is the polytropic constant.

PREREQUISITES
  • Understanding of the ideal gas law (PV=nRT)
  • Knowledge of isentropic processes in thermodynamics
  • Familiarity with the concept of polytropic constants (gamma)
  • Basic skills in algebra for rearranging equations
NEXT STEPS
  • Study isentropic compression and its equations in thermodynamics
  • Learn how to calculate the polytropic constant (gamma) for air
  • Explore the relationships for ideal gases during adiabatic processes
  • Practice problems involving the ideal gas law and temperature conversions
USEFUL FOR

Students studying thermodynamics, automotive engineers, and anyone involved in engine performance analysis will benefit from this discussion.

wcbryant87
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Homework Statement



A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains 499 cm cubed of air at atmospheric pressure (1.01E5 Pa) and a temperature of 27.0 degrees C. At the end of the stroke, the air has been compressed to a volume of 46.2 cm cubed and the gauge pressure has increased to 2.72E6.

What is the final temperature

Homework Equations



P1*V1/T1 = P2*V2/T2



The Attempt at a Solution



I followed the equation that I posted above. Here is what it looked like.

(1.01E5 * 499 cm cubed)/ 27 = (2.72E6 * 46.2)/x

Solving for x, I got x = (2.72E6*46.2)/1866629.63 = 66.8 degrees C

Problem is, that answer is apparently wrong. Am I missing something here?

Thanks for the help!
 
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Try changing your temperature to kelvin :)
 
well it wants the answer in celsius. Does that equation have to be done with Kelvin units?
 
Were you given that equation? As you won't find T2 like that. Even if you use kelvin as the pv/pv is a ratio, it won't make any difference.

Hint: Expansion and compression is isentropic.
 
No I wasn't given any equation. I thought that that one would work though because I was only missing one variable.

Do I use pv=nrt?
 
If you've got a book, look up isentropic compression.

pv^gamma = constant.

where gamma is the polytropic constant you'll have to find the relationship between temperature and anther variable.
 
xxChrisxx said:
If you've got a book, look up isentropic compression.

pv^gamma = constant.

where gamma is the polytropic constant you'll have to find the relationship between temperature and anther variable.
Thats the Adiabatic process.

Calculate the mass of air in the cylinder from pv=mRT

Constants for air Cp=1005J/kgK, Cv=718J/kgK R=287J/kgK, calculate gamma from these.

Reaarange the equation for an adiabatic process to find T
 
its both acutally, as isentropic is adiabatic and reversible. to find the temperatre after compression you don't need the mass in the cylinder as it comes out in the wash.

the relationships for isentropic processes for ideal gases are listed in any thermo textbook. but as this is homework help I am not going to just give them out.
 
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