What is the Relationship Between Entropy and Temperature?

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The discussion centers on the relationship between entropy (S) and temperature (T) in the context of the second law of thermodynamics. Participants are trying to demonstrate that the proportionality constant λ in the equation dS = λ * dQ is equal to 1/T. Clarification is sought on the definitions of entropy, heat (Q), and temperature, as well as the dimensional differences between S and Q. The conversation emphasizes the need for a solid understanding of these concepts to prove the equation dS = dQ/T. Overall, the thread highlights the complexities of thermodynamic principles and the mathematical relationships involved.
HmJeremy
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Homework Statement
Thermodynamics - entropy - second law
Relevant Equations
dS = λ*dQ ----> dS = dQ/T , where λ = 1/T
Help!
Hi, I need
in the secodn law of thermodynamic, we have the ENTROPY "S".

Well, I need help for this:
We have dS ≈ dQ

Then we have dS = λ *dQ
where we have λ = λ (T, ... )

I have to demostrate that :
λ = 1/T , where T = temperature.

Thanks for the advices and help!
 
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To be able to prove that ##dS = \frac{dQ}{T}##, you need to start with the definitions of ##S, Q## and ##T##. What definitions are you supposed to start with?
 
HmJeremy said:
We have dS ≈ dQ
We do? S and Q have different dimensions!Then we have dS = λ *dQ
where we have λ = λ (T, ... )

I have to demostrate that :
λ = 1/T , where T = temperature.

Thanks for the advices and help!
[/QUOTE]
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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