Thermodynamics: Einstein solid (simple step in derivation)

  • Thread starter iScience
  • Start date
  • #1
466
5
S=kln([itex]\frac{eq}{N}[/itex])N --->= S=Nkln([itex]\frac{q}{N}+1[/itex])

i understand that the e goes away and the N exponent comes down but where does the +1 come from?
 

Answers and Replies

  • #2
Dick
Science Advisor
Homework Helper
26,260
619
S=kln([itex]\frac{eq}{N}[/itex])N --->= S=Nkln([itex]\frac{q}{N}+1[/itex])

i understand that the e goes away and the N exponent comes down but where does the +1 come from?

That's not even right. kln((eq/N)^N)=Nk(1+ln(q/N)). Use more parentheses to show what you really mean. Just use rules of logarithms, and show how you are using them.
 
  • #3
466
5
there are no more parentheses that's what's in my book. is this even an approximation??
 
  • #4
Dick
Science Advisor
Homework Helper
26,260
619
there are no more parentheses that's what's in my book. is this even an approximation??

No, I think it's just wrong.
 

Related Threads on Thermodynamics: Einstein solid (simple step in derivation)

  • Last Post
Replies
1
Views
937
Replies
3
Views
7K
  • Last Post
Replies
1
Views
4K
  • Last Post
Replies
3
Views
4K
Replies
0
Views
4K
Replies
4
Views
10K
Replies
2
Views
3K
Replies
1
Views
3K
Replies
0
Views
1K
Top