- #1

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^{N}--->= S=Nkln([itex]\frac{q}{N}+1[/itex])

i understand that the e goes away and the N exponent comes down but where does the +1 come from?

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- Thread starter iScience
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- #1

- 466

- 5

i understand that the e goes away and the N exponent comes down but where does the +1 come from?

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- #2

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iScience said:^{N}--->= S=Nkln([itex]\frac{q}{N}+1[/itex])

i understand that the e goes away and the N exponent comes down but where does the +1 come from?

That's not even right. kln((eq/N)^N)=Nk(1+ln(q/N)). Use more parentheses to show what you really mean. Just use rules of logarithms, and show how you are using them.

- #3

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there are no more parentheses that's what's in my book. is this even an approximation??

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iScience said:there are no more parentheses that's what's in my book. is this even an approximation??

No, I think it's just wrong.

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