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Thermodynamics: Einstein solid (simple step in derivation)

  1. Sep 22, 2013 #1
    S=kln([itex]\frac{eq}{N}[/itex])N --->= S=Nkln([itex]\frac{q}{N}+1[/itex])

    i understand that the e goes away and the N exponent comes down but where does the +1 come from?
     
  2. jcsd
  3. Sep 22, 2013 #2

    Dick

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    That's not even right. kln((eq/N)^N)=Nk(1+ln(q/N)). Use more parentheses to show what you really mean. Just use rules of logarithms, and show how you are using them.
     
  4. Sep 23, 2013 #3
    there are no more parentheses that's what's in my book. is this even an approximation??
     
  5. Sep 23, 2013 #4

    Dick

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    No, I think it's just wrong.
     
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