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Thermology,calorimetry , help with lesson

  1. Mar 27, 2012 #1
    200 g of ice at -20 ° C are placed in an adiabatic container walls containing certain amount of water at 80 ° C. After heat exchange, temperature equilibrium is θ = 40 ° C. Calculate the quantity of water contained in the container prior to blending. Data: specific heat of ice cG = 0.5 cal / g. ° C, latent heat of fusion of ice L = 80 cal / g, specific heat of water and water = 1 cal / g. ° C

    This was my response

    M = Q*c * ∆T = 200 * 0.5 * 20 (because it goes until it reaches 0 ° C) = 2000 cal, Q = m * l 200 * 80 = 16000 cal, now the ice is in the liquid state 200*1* 40 =8000 => Qtotal ice as there is heat exchange quantities of heat are balanced => 26000=Ma*1*40 = 650g

    right? I'm helping a friend and want to make sure it's right
    sorry I do not speak English well, i am from Brazil and i am still in high school . Sorry the inconvenience
     
  2. jcsd
  3. Mar 27, 2012 #2

    K^2

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    Looks good. That's what you're supposed to do, and all the algebra seems to be correct.
     
  4. Mar 27, 2012 #3
    Thank you. Now I am relaxed
     
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