Thin-film interference question

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SUMMARY

The discussion centers on a thin-film interference problem involving a film with a refractive index of 1.333 and a thickness of 340 nm. The key equation used is t(min) = λ/(2*n(film)), which determines the minimum film thickness for maximum transmittance. The calculated wavelength of 906 nm exceeds the visible spectrum, indicating a misunderstanding in the application of the formula. The correct approach involves identifying wavelengths between 780 nm and 390 nm for optimal transmission, confirming that violet (C) is the correct answer.

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Homework Statement


The table lists the range of wavelengths in vacuum corresponding to a given color. If one looks through a film which has a refractive index of 1.333 and thickness of 340 nm (nanometers), which color will be 100% transmitted through the film?

Table (Color/Wavelength):
  • red/780nm-622nm
  • orange/622nm-597nm
  • yellow/597nm-577nm
  • green/577nm-492nm
  • blue/492nm-455nm
  • violet/455nm-390nm

A) red
B) yellow
C) violet
D) green
E) white

Homework Equations


refractive index of air is 1, so n(air)<n(film)>n(air) condition is met. relevant equations will be:
t(min)=\frac{\lambda}{2*n(film)}

where n(film) is the refractive index of the film and t(min) is minimum film thickness

The Attempt at a Solution


I tried this problem, making n(film)=1.333 and t(min)=340 nm, solving for \lambda.
I got \lambda=2*n(film)*t(min)=2*1.333*340=906nm
However, this exceeds the wavelength for any of the colors, and the answer should be (C). What did I do wrong?
 
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You get maximum transmittance through the film if its thickness is any integer multiple of lambda/(2n)



ehild
 
yeah, but how do you come up with the correct wavelength?
 
Find the possible wavelengths which are between 780nm and 390 nm. All of them are correct.

ehild
 
how this relationship between thickness, refractive index and wavelength is obtained? is there any relationship between complex refractive index with film thickness?
 
Uhh, I don't think so. The refractive index depends on the material the medium is made of, and that's it. What I was asking here was an interference question. When the medium is at a certain thickness, the light reflected from one end of the medium interferes with that from the other end to cancel each other out.
 

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