Things i forgot how to do/unsure about. Porabola stuff

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Homework Help Overview

The discussion revolves around understanding the properties of parabolas, specifically focusing on finding the vertex, x-intercepts, and the effects of parameters a, h, and k in the vertex form of a quadratic equation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to identify the vertex and x-intercepts of a parabola given in vertex form. They express uncertainty about finding the x-intercepts and seek hints for clarification. Other participants provide insights on setting y to zero to find x-intercepts and discuss the implications of the parameters on the graph's shape.

Discussion Status

Some participants have confirmed the original poster's understanding of the vertex and the effects of parameters a, h, and k. Guidance has been offered regarding the method to find x-intercepts, though there is no explicit consensus on the correctness of the approaches discussed.

Contextual Notes

The original poster mentions feeling unsure and "braindead," indicating a potential struggle with the material. There is also a request for hints rather than complete solutions, aligning with the forum's learning-first approach.

MrNonexistent
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Homework Statement


1) find the vertex, 2) find the x intercepts in terms of a, h, and k, 3) explain how values of a, h, and k affect the graph


Homework Equations


y = A(x - h)^2 + k


The Attempt at a Solution


1) (H,K)
2) aaaahhh i don't know... i just forgot.
3) A determines how wide it is, with a bigger a making a skinnier parabola, a smaller A making a wider parabola, and a negative a making it go upside down. H moves the vertex along the x axis, and K moves it along the Y axis.


is the ones i answered right? also. i would really appreciate a hint as to how to find out 2.

thanks guys
 
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2. In order for you to be on the x-axis, set y=0. So from there, just solve for x. Whenever a problem says solve "x" in terms of a, b, c ... etc., they just want you to have it look like x = a, b, c.

1 & 3 are good.
 
ooo... hm let's check it out.
 
im getting that

A(x-h)^2 = [tex]\sqrt{-k}[/tex]

gives you one and if you subtract -K from this answer, you get the other x axis.
 
x = [tex]\frac{\sqrt{-k}}{A} \pm AH[/tex]


is that right? i am so braindead.
 

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