I know this might be easy but i forgot how to solve

[idiotblue]

Please help me..

integrate this

$$\int$$$$\frac{1}{U\sqrt{1-U^2}}dU$$

 

[rock.freak667]

..Try using integration by parts and see if you can solve

u=$\frac{1}{U}$ find du/dx
$\frac{dv}{dx}=\frac{1}{\sqrt{1-U^2}}$ so get v=

and

$$\int u\frac{dv}{dx}dx=uv-\int v\frac{du}{dx}dx$$

 

[Dick]

It can be done straightforwardly with a trig substitution, like u=sin(t).

 

[idiotblue]

Sorry but...

the original question wasintegration from $$\epsilon$$to$$\pi-\epsilon$$
$$\int$$$$\frac{1}{sinx}dx$$

I tried to integrate it straight but i don't know how calculate cosec and cot...

 

[Avodyne]

Try the substitution u = tan(x/2).

 

[idiotblue]

:)thanks guys. I got it~

 

[cummins]

What is the term for the slope on an x-axis that runs parallel but never actually touches the x axis?

 

[Dick]

Get your own thread. But until you do 'horizontal asymptote with y value 0'.