Things i forgot how to do/unsure about. Porabola stuff

  • Thread starter Thread starter MrNonexistent
  • Start date Start date
AI Thread Summary
The discussion focuses on understanding the properties of parabolas defined by the equation y = A(x - h)^2 + k. Participants confirm that the vertex is located at (h, k) and discuss how the parameters a, h, and k influence the graph's shape and position. Specifically, a affects the width and direction of the parabola, while h and k shift the vertex along the x and y axes, respectively. To find the x-intercepts, users are advised to set y to zero and solve for x, leading to a formula involving the parameters. Overall, the conversation emphasizes clarifying these concepts and solving for x-intercepts in terms of a, h, and k.
MrNonexistent
Messages
11
Reaction score
0

Homework Statement


1) find the vertex, 2) find the x intercepts in terms of a, h, and k, 3) explain how values of a, h, and k affect the graph


Homework Equations


y = A(x - h)^2 + k


The Attempt at a Solution


1) (H,K)
2) aaaahhh i don't know... i just forgot.
3) A determines how wide it is, with a bigger a making a skinnier parabola, a smaller A making a wider parabola, and a negative a making it go upside down. H moves the vertex along the x axis, and K moves it along the Y axis.


is the ones i answered right? also. i would really appreciate a hint as to how to find out 2.

thanks guys
 
Physics news on Phys.org
2. In order for you to be on the x-axis, set y=0. So from there, just solve for x. Whenever a problem says solve "x" in terms of a, b, c ... etc., they just want you to have it look like x = a, b, c.

1 & 3 are good.
 
ooo... hm let's check it out.
 
im getting that

A(x-h)^2 = \sqrt{-k}

gives you one and if you subtract -K from this answer, you get the other x axis.
 
x = \frac{\sqrt{-k}}{A} \pm AH


is that right? i am so braindead.
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

Similar threads

Replies
8
Views
2K
Replies
6
Views
2K
Replies
2
Views
2K
Replies
4
Views
2K
Replies
6
Views
2K
Replies
3
Views
2K
Back
Top