MHB This is known as the Sector Area Formula.

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To find the area of a circular sector when given an angle of $240^{\circ}$, first determine the angle inside the sector, which is $120^{\circ}$. This angle represents one-third of the full circle, as calculated by $120/360$. Consequently, the area of the sector is also one-third of the total area of the circle. The generalized formula for the area of a sector with angle $\theta$ in radians is $A = \frac{1}{2} \theta r^2$. Understanding these relationships allows for easier calculations of sector areas.
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hello guys..

how to figure it out this below problem, find area of circle

please, see my picture..

thanks...

susanto3311
 

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What are your thoughts here on what you should do?
 
i confused about 240...how to elaborate with commonly area formula?
 
If $240^{\circ}$ is outside the sector whose area we want, then what angle is inside, and then what portion of the whole is this?

Can we generalize from this to get a formula for the area of a circular sector?
 
can you make to me more simple, i think be illustrated with my problem sample.
 
A circle "encloses" $360^{\circ}$...if $240^{\circ}$ is outside the sector we want, how much is inside?
 
hi Mark..

360-240 = 120, then...how to elaborate?...
 
What portion of 360 is 120?
 
MarkFL said:
What portion of 360 is 120?

=120/360=0.333, so...
 
  • #10
Actually, we have:

$$\frac{120}{360}=\frac{1}{3}$$

So, what portion of the area of the whole circle do you suppose the area of the sector would be?
 
  • #11
MarkFL said:
Actually, we have:

$$\frac{120}{360}=\frac{1}{3}$$

So, what portion of the area of the whole circle do you suppose the area of the sector would be?

hi Mark, finally
i think like this :

It's true, Mark?
 

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  • #12
Yes, since 1/3 of the total angle within the circle is subtended by the sector, then its area is 1/3 of the whole circle. So, we could generalize and state that if the angle subtended within two radii of a circular sector is $\theta$ (given in radians) then the area $A$ of the sector is:

$$A=\frac{\theta}{2\pi}\cdot\pi r^2=\frac{1}{2}\theta r^2$$
 

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