This is the correct Derivative?

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SUMMARY

The discussion revolves around finding the derivative of the function y=log(x)/2-log(x), which simplifies to y=log(x)*(2-log(x))^-1. The participant correctly identifies the derivative of log(x) as 1/(xln(10)) and attempts to derive the expression for (2-log(x))^-1. However, they encounter errors in their calculations, particularly in the application of the chain rule and the placement of negative signs. The correct derivative is confirmed to be 2/(xln(10)(2-log(x))^2.

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Homework Statement



Need to find the derivative:

y=logx/2-logx=logx*(2-log(x))^-1

The Attempt at a Solution



The derivative of log(x) is 1/xln(10) and the derivative of (2-log(x))^-1 is -(2-log(x))^-2*1/xln(10)?

This ended as

1/xln(10)(2-logx) - logx/xln(10)(2-log(x))^2

2-log(x)-log(x)/xln(10)(2-log(x))^2


Though the answer is 2/xln(10)(2-log(x))^2... so what am I doing wrong?
 
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In general, more brackets and/or spaces would help. TeX syntax is even better: ##\frac{\log(x)}{x}##.

1/xln(10)(2-logx) - logx/xln(10)(2-log(x))^2
I think you are missing ^(-1) in the first part and a minus sign in the second part. I don't see how the following line follows from that expression.
The answer is missing a minus, too?
 

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